document.write( "Question 144143: Hello. Please help me solve this problem: I need to find the simplest radical form and the approximate answer of \"sqrt+%285%29-1%2Fx+=+sqrt+%285%29%2F2\".
\n" ); document.write( "\"2%28sqrt%285%29-2%2Fx=sqrt%285%29\"
\n" ); document.write( "\"sqrt%285%29-2%2Fx=0\"
\n" ); document.write( "\"sqrt%285%29=2%2Fx\"
\n" ); document.write( "\"x%28sqrt%285%29%29=2\"
\n" ); document.write( "\"x=2%2Fsqrt%285%29\"
\n" ); document.write( "x = 0.8944
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Algebra.Com's Answer #853930 by MathTherapy(10801)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hello. Please help me solve this problem: \r\n" );
document.write( "I need to find the  simplest radical form and the approximate answer of \"sqrt+%285%29-1%2Fx+=+sqrt+%285%29%2F2\".\r\n" );
document.write( "\"2%28sqrt%285%29-2%2Fx=sqrt%285%29\"\r\n" );
document.write( "\"sqrt%285%29-2%2Fx=0\"\r\n" );
document.write( "\"sqrt%285%29=2%2Fx\"\r\n" );
document.write( "\"x%28sqrt%285%29%29=2\"\r\n" );
document.write( "\"x=2%2Fsqrt%285%29\"\r\n" );
document.write( "x = 0.8944\r\n" );
document.write( "*****************\r\n" );
document.write( "         \"sqrt%285%29+-+1%2Fx+=+sqrt%285%29%2F2\"\r\n" );
document.write( "    \"2x%2Asqrt%285%29+-+2+=+x%2Asqrt%285%29\" ---- Multiplying by LCD, 2x\r\n" );
document.write( "\"2x%2Asqrt%285%29+-+x%2Asqrt%285%29+=+2\" \r\n" );
document.write( "          \"x%2Asqrt%285%29+=+2\"\r\n" );
document.write( "      \"%28x%2Asqrt%285%29%29%5E2+=+2%5E2\" ----- Squaring each side\r\n" );
document.write( "       \"x%5E2%285%29+=+4\"\r\n" );
document.write( "           \"x%5E2+=+4%2F5\"\r\n" );
document.write( "            \r\n" );
document.write( "\r\n" );
document.write( "However, the negative x-value, \"-2sqrt%285%29%2F5\" is EXTRANEOUS, therefore leaving the sole VALID x-value, \"highlight%282sqrt%285%29%2F5%29\". \r\n" );
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document.write( "Great job!! You got up to this point: \"x=2%2Fsqrt%285%29\", but needed to go a little further, by RATIONALIZING the\r\n" );
document.write( "DENOMINATOR, as demonstrated above. Your decimal approximation, x = 0.8944, is also CORRECT.\r\n" );
document.write( "I don't know why you sought help. You didn't need it!\r\n" );
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document.write( "Again, great job!!
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