document.write( "Question 1003361: If 1 is a zero of p(x) =ax^3-(a-1)x-1 then find value of a \n" ); document.write( "
Algebra.Com's Answer #853928 by ikleyn(53742)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "If 1 is a zero of p(x) = ax^3-(a-1)x-1 then find value of a
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\n" ); document.write( "\n" ); document.write( "In his post, @mananth deduces that,  under given condition,  the value of  ' a '  must be  1.\r
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        It is a crude and a danger logical mistake.

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\n" ); document.write( "\n" ); document.write( "Actually,  a  ' 1 '  is a root of a polynomial   p(x) = ax^3 - (a-1)x - 1  for  \"highlight%28highlight%28ANY%29%29\"  value of  ' a ',\r
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\n" ); document.write( "\n" ); document.write( "Indeed,  for every such a polynomial  p(x),   p(1) = a - (a-1) - 1 === 0  identically for any value of  'a'.\r
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\n" ); document.write( "\n" ); document.write( "So, from the given condition,  we can not determine a value of  ' a ' : it can be  \"highlight%28highlight%28ANY%29%29\"  number/value.\r
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\n" ); document.write( "\n" ); document.write( "I don't know if this problem is a mathematical joke or a  TRAP  to catch
\n" ); document.write( "a hapless student,  or a mistake of the problem's creator,  but what I said is the  FACT.\r
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\n" ); document.write( "\n" ); document.write( "If it is a  trap,  then @mananth has fallen in this trap and invites all his readers to follow him.\r
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