document.write( "Question 1007654: A person rowed their boat downstream for 100 miles and they took 2 hours. Returning upstream, the trip took 2 hours and 40 minutes.\r
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Algebra.Com's Answer #853921 by ikleyn(53742)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "A person rowed their boat downstream for 100 miles and they took 2 hours.
\n" ); document.write( "Returning upstream, the trip took 2 hours and 40 minutes.
\n" ); document.write( "What is the speed of the water?
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\n" ); document.write( "\n" ); document.write( "        In the post by @mananth, the solution is produced by a computer code.\r
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\n" ); document.write( "\n" ); document.write( "        Neither the style of the solution, nor its form of presentation are perfect; \r
\n" ); document.write( "\n" ); document.write( "        they are difficult to read and to understand.\r
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\n" ); document.write( "\n" ); document.write( "        So, I present here my solution in simple, straightforward and clear, transparent form,\r
\n" ); document.write( "\n" ); document.write( "        as it should be done to every school Math problem.\r
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document.write( "Let x be the rate of the boat in still water (in miles per hour)\r\n" );
document.write( "and y be the rate of the current (in the same units).\r\n" );
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document.write( "Then the effective rate of the boat downstream is x + y\r\n" );
document.write( "and  the effective rate of the boat   upstream is x - y.\r\n" );
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document.write( "From the problem, the effective rate of the boat downstream is the distance of 100 miles \r\n" );
document.write( "divided by the time of 2 hours  \"100%2F2\" = 50 mph.\r\n" );
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document.write( "                  The effective rate of the boat upstream is the distance of 100 miles \r\n" );
document.write( "divided by the time of 2 hours and 40 minute, or  2\"2%2F3\" hours, or  \"8%2F3\" hours\r\n" );
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document.write( "    \"100%2F%28%288%2F3%29%29\" = \"300%2F8\" = 37.5 mph\r\n" );
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document.write( "So, we have two equations for  'x'  and  'y'\r\n" );
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document.write( "    x + y = 50,      (1)\r\n" );
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document.write( "    x - y = 37.5.    (2)\r\n" );
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document.write( "To find 'y', subtract equations (2) from equation (1).  The terms 'x' and 'x' will cancel each other, and you will get\r\n" );
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document.write( "    2y = 50 - 37.5 = 12.5  --->   y = 12.5/2 = 6.25.\r\n" );
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document.write( "At this point, the solution is complete.\r\n" );
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document.write( "ANSWER.  The rate of the current is 6.25 miles per hour.\r\n" );
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\n" ); document.write( "\n" ); document.write( "For a computer code (which @mananth uses to create his solution files),
\n" ); document.write( "there is no difference which style of the solution to produce.\r
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\n" ); document.write( "\n" ); document.write( "But for a human reader, there is a huge difference what to read and from which source to learn.\r
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\n" ); document.write( "\n" ); document.write( "So, I created my solution here in order for you see the difference.\r
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