document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004151>Question 1004151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you are standing at the top of a 500m tall building. across the street is a shorter building. at ground level, the two buildings are 50 meters apart, and if you measure the angle of depression from the top of your building to the nearest edge of the shorter building, you get an angle of pi/6. how tall is the other building?\r<BR>\n" );
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document.write( "a) 500 - 50 sqrt 2 meters<BR>\n" );
document.write( "b) 500 - 50/sqrt 2 meters<BR>\n" );
document.write( "c) 500 - 25/sqrt 2 meters<BR>\n" );
document.write( "d) 500-50/sqrt 3 meters<BR>\n" );
document.write( "e) 500 - 25 sqrt 2 meters<BR>\n" );
document.write( "f) 500 - 50 sqrt 3 meters </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #853911 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39790)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=853911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Drawing used on paper but\r<BR>\n" );
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document.write( "the other building tallness, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=500-50%2Atan%28pi%2F6%29 ALIGN=MIDDLE  ALT=\"500-50%2Atan%28pi%2F6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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