document.write( "Question 1026395: The product of two consecutive odd integers is 6 more than 5 times the smaller number, find both numbers \n" ); document.write( "
Algebra.Com's Answer #853901 by ikleyn(53646) You can put this solution on YOUR website! . \n" ); document.write( "The product of two consecutive odd integers is 6 more than 5 times the smaller number, find both numbers \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " The \"solution\" in the post by @mananth is INCORRECT,\r \n" ); document.write( "\n" ); document.write( " since he incorrectly solved the quadratic equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " See my reasoning below.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let 'n' be the smaller of the two odd consecutive integers.\r\n" ); document.write( "Then the greater add consecutive integer is (n+2).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Our equation is\r\n" ); document.write( "\r\n" ); document.write( " n*(n+2) = 5n + 6,\r\n" ); document.write( "\r\n" ); document.write( " n^2 + 2n = 5n + 6,\r\n" ); document.write( "\r\n" ); document.write( " n^2 - 3n - 6 = 0.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The discriminant is d = b^2 - 4ac = (-3)^2 - 4*1*(-6) = 9 + 24 = 33.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved correctly.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |