document.write( "Question 24316: 9x+6y=14
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document.write( "3x+2y=11
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document.write( "Solve for x and y\r
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document.write( "I know that you have to use substitution but i keep getting answers like,
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document.write( "9x+66-9x=14 so it is going to turn out with your x's turning into a zero and you come out with 0=52 and that is obviousley not true...PLEASE HELP ASAP I have been working on this for at least an hour\r
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document.write( "i looked for examples similiar to this problem but i could'nt find any
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Algebra.Com's Answer #853897 by greenestamps(13326) You can put this solution on YOUR website! \n" ); document.write( "You say you are ending up with an equation that says something like \"0=52\". \n" ); document.write( "You are probably doing the algebra correctly; now you just need to learn what that result means. \n" ); document.write( "As you say, \"0=52\" is not true; that equation has no solutions. Assuming you did the algebra correctly, that means the original pair of equations has no solution. \n" ); document.write( "When you are first learning algebra, it is important that you recognize this kind of result and understand what it means. \n" ); document.write( "An experienced student can look at this pair of equations and see that the \"9x+6y\" in the first equation is just 3 times the \"3x+2y\" in the second equation. If you see that, then you can multiply the second equation by 3, making the pair of equations \n" ); document.write( "9x+6y=14 \n" ); document.write( "9x+6y=-33 \n" ); document.write( "The expressions on the left are identical, so the expressions on the right should be identical. Since they are not, the system of equations has no solution. \n" ); document.write( " \n" ); document.write( " |