document.write( "Question 1188420: a) A total of $40,000 was invested, part of it at 12% interest and the remainder at 15%.
\n" ); document.write( "If the total yearly interest from both investments was $5,800. How much was invested at each rate \n" ); document.write( "

Algebra.Com's Answer #853886 by josgarithmetic(39790) $\"\"$ $\"About$

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document.write( "RATE            AMT.INV.         INTEREST\r\n" );
document.write( " 12              40000-y         0.12(40000-y)\r\n" );
document.write( " 15               y              0.15y\r\n" );
document.write( "                40000             5800\r\n" );
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\n" ); document.write( " $\"12%2840000-y%29%2B15y=580000\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"12%2A40000-12y%2B15y=580000\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%2815-12%29y=580000-12%2A40000\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28y=%28580000-12%2A40000%29%2F%2815-12%29%29\"$
\n" ); document.write( "Just simplify and compute this, and then evaluate the other invested quantity.\r
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\n" ); document.write( "\n" ); document.write( "The amount at 15% looks like to be 33333.33 dollars. \n" ); document.write( "

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