document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1107789>Question 1107789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jane took 30 min to drive her boat upstream to&#8203; water-ski at her favorite spot. Coming back later in the&#8203; day, at the same boat&#8203; speed, took her 15 min. If the current in that part of the river is 6 km per&#8203; hr, what was her boat speed in still&#8203; water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #853865 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13296)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=853865\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The responses from the other tutors show solutions using an equation that says the distances the two directions are the same.<br><BR>\n" );
document.write( "A different setup makes the algebra needed to solve the problem easier.<br><BR>\n" );
document.write( "Since the distances are the same and the time returning is half the time going, the speed returning is twice the speed going.<br><BR>\n" );
document.write( "Let the boat speed by x; then the speed going is x-6 and the speed returning is x+6:<br><BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=18=x ALIGN=MIDDLE  ALT=\"18=x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "ANSWER: 18 km/hr<br><BR>\n" );
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