document.write( "Question 1038207: Paul can do a certain job in half the time that Jim requires to do it. Jim worked alone for an hour and stopped; then Paul completed the job in 10 hours. What length of time, in hours, would Paul, working alone, take to do the whole job? \n" ); document.write( "
Algebra.Com's Answer #853864 by KMST(5337) You can put this solution on YOUR website! Jim worked alone for \n" ); document.write( "Paul comes in, sees the work Jim did in \n" ); document.write( "\"It would have taken me \n" ); document.write( "After Paul worked another \n" ); document.write( "Then Jim said \"SEE!, I could have done the whole thing in \n" ); document.write( " \n" ); document.write( "The problem with mananth solution seems to be that after getting to \n" ); document.write( "((x-1)/x)/(2/x)=10 or \n" ); document.write( "\"I could simplify the left side expression by writing it as \n" ); document.write( "or I could simplify the equation by multiplying both sides by \n" ); document.write( "Then mananth had one of those brain-farts and multiplied the left hand side times \n" ); document.write( "Keeping the equal sign in between, mananth concluded that Jim could have done the whole job in 2 hours, forgetting that it took Jim 10 hours to do part of the job. \n" ); document.write( "We we all have one of those brain farts now and then. One professor told about answering a problem on a radio station show by saying that the top of an 8 foot ladder leaning again the side of a house would be 10 feet above the ground. \n" ); document.write( " |