document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1031819>Question 1031819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a particular rectangle is 8 inches more than 2 times its width. A new rectangle is formed by tripling the width. The area is 30 square inches more than the area of original rectangle. Find the dimensions of the original rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #853863 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39736)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=853863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w, the width of the original rectangle.<BR>\n" );
document.write( "Length described as 2w+8.<BR>\n" );
document.write( "Area, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w%282w%2B8%29 ALIGN=MIDDLE  ALT=\"w%282w%2B8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "New rectangle of width 3w.<BR>\n" );
document.write( "Length unchanged, 2w+8.<BR>\n" );
document.write( "Area, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3w%282w%2B8%29 ALIGN=MIDDLE  ALT=\"3w%282w%2B8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Increase of area is 30 square inches.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3w%282w%2B8%29-w%282w%2B8%29=30 ALIGN=MIDDLE  ALT=\"3w%282w%2B8%29-w%282w%2B8%29=30\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Simplify and solve. </SPAN>\n" );
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