document.write( "Question 1031819: The length of a particular rectangle is 8 inches more than 2 times its width. A new rectangle is formed by tripling the width. The area is 30 square inches more than the area of original rectangle. Find the dimensions of the original rectangle. \n" ); document.write( "

Algebra.Com's Answer #853861 by ikleyn(53618) $\"\"$ $\"About$

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\n" ); document.write( "The length of a particular rectangle is 8 inches more than 2 times its width. A new rectangle is formed by tripling
\n" ); document.write( "the width. The area is 30 square inches more than the area of original rectangle. Find the dimensions of the original
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\n" ); document.write( "\n" ); document.write( "The solution in the post by @mananth is incorrect due to an arithmetic error on the way.
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document.write( "let width be x\r\n" );
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document.write( "length will be 2x+8\r\n" );
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document.write( "Area = x(2x+8)\r\n" );
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document.write( "A new rectangle is formed by tripling the width.\r\n" );
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document.write( "new width = 3x\r\n" );
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document.write( "length = 2x+8\r\n" );
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document.write( "Area = 3x(2x+8)\r\n" );
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document.write( "The area is 30 square inches more than the area of original rectangle.\r\n" );
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document.write( "3x(2x+8) -x(2x+8)=30\r\n" );
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document.write( "2x(2x+8) = 30\r\n" );
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document.write( "4x^2 + 16x - 30 = 0\r\n" );
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document.write( "2x^2 +  8x - 15 = 0\r\n" );
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document.write( " = \r\n" );
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document.write( "Taking positive value width =  = 1.39116 inches, approximately.\r\n" );
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document.write( "Length = 2x+8 = 2*1.39116+8 = 10.78232 inches, approximately.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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