document.write( "Question 1031850: A man is 4 times old as his daughter was 3 years ago.If their combined ages is 48,how old is the daughter now?
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Algebra.Com's Answer #853859 by josgarithmetic(39736)\"\" \"About 
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document.write( "                       Three years ago         Now\r\n" );
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document.write( "MAN                        -                   4(d-3)\r\n" );
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document.write( "DAUGHTER                   d-3                  d\r\n" );
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document.write( "SUM                                            48\r\n" );
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\n" ); document.write( "\"4%28d-3%29%2Bd=48\"\r
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\n" ); document.write( "\n" ); document.write( "\"4d-12%2Bd=48\"\r
\n" ); document.write( "\n" ); document.write( "\"5d=48%2B12\"\r
\n" ); document.write( "\n" ); document.write( "\"5d=60\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28d=12%29\", daughter's age
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