document.write( "Question 1031850: A man is 4 times old as his daughter was 3 years ago.If their combined ages is 48,how old is the daughter now?
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Algebra.Com's Answer #853857 by ikleyn(53618) $\"\"$ $\"About$

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\n" ); document.write( "A man is 4 times $\"highlight%28highlight%28as%29%29\"$ old as his daughter was 3 years ago.
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\n" ); document.write( "\n" ); document.write( "        The solution in the post by @mananth is incorrect.\r
\n" ); document.write( "\n" ); document.write( "        It is incorrect, since his setup equation is wrong.\r
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\n" ); document.write( "\n" ); document.write( "        I came to bring a correct solution.\r
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document.write( "Let the daughter age be x now.\r\n" );
document.write( "3 years ago her age was (x-3) years.\r\n" );
document.write( "Father's age now is 4(x-3)\r\n" );
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document.write( "Our equation is\r\n" );
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document.write( "    x + 4(x-3) = 48    (the combined age)\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    x + 4x - 12 = 48\r\n" );
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document.write( "      5x        = 60\r\n" );
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document.write( "       x        = 60/5 = 12.\r\n" );
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document.write( "ANSWER.  The daughter is 12 years old.  The father is 4(x-3) = 4*(12-3) = 4*9 = 36 years old.\r\n" );
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document.write( "CNECK.  Their combined age is 12 + 36 = 48,  which is precisely correct.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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