document.write( "Question 1031863: frank went 16 miles at one speed and then caame back going 4mph faster. if the return trip took 40mins less time find the 2 speeds. \n" ); document.write( "

Algebra.Com's Answer #853856 by josgarithmetic(39736) $\"\"$ $\"About$

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$\"SPEED%2ATIME=DISTANCE\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"TIME=DISTANCE%2FSPEED\"$ \r
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document.write( "            SPEEDS         TIME            DISTANCE\r\n" );
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document.write( "WENT            r            16/r             16\r\n" );
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document.write( "BACK            r+4          16/(r+4)         16\r\n" );
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document.write( "DIFFERENCE                   2/3\r\n" );
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document.write( "40 minutes is  hour.\r\n" );
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\n" ); document.write( " $\"16%2Fr-16%2F%28r%2B4%29=2%2F3\"$ \r
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