document.write( "Question 1115269: Meisha has $25,000 that she wants to invest. She invests it in accounts paying 12%, 7%, and
\n" ); document.write( "6% simple interest. The account paying 12% is a higher-risk account, so she wants the
\n" ); document.write( "amount in that account to be half of the amount she has in the account paying 6% simple
\n" ); document.write( "interest. If her annual interest is $1945, how much is invested at each rate?
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Algebra.Com's Answer #853831 by josgarithmetic(39780)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "         AMOUNT IN ACCOUNT      RATE(%)        INTEREST\r\n" );
document.write( "               x                 12             0.12x\r\n" );
document.write( "              25000-x-2x          7             0.07(25000-x-2x)\r\n" );
document.write( "               2x                 6             0.06*2x\r\n" );
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document.write( "TOTALS       25000                              1945\r\n" );
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\r
\n" ); document.write( "\n" ); document.write( "\"0.12x%2B0.07%2825000-x-2x%29%2B0.06%2A2x=1945\"\r
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\n" ); document.write( "\n" ); document.write( "\"12x%2B7%2825000-3x%29%2B6%2A2x=194500\"\r
\n" ); document.write( "\n" ); document.write( "\"24x%2B7%2A25000-21x=194500\"\r
\n" ); document.write( "\n" ); document.write( "\"3x=194500-7%2A25000\"\r
\n" ); document.write( "\n" ); document.write( "\"3x=19500\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=6500%29\"\r
\n" ); document.write( "\n" ); document.write( "6500 at 12%
\n" ); document.write( "13000 at 6%
\n" ); document.write( "5500 at 7%
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