document.write( "Question 1210578: A standard 55 gallon drum is holding oil. A portion of the oil is removed. A stick with inch measurements is placed in the drum. The remaining level is 2 7/8 inches. Determine amount (gallons) remaining in drum.\r
\n" ); document.write( "\n" ); document.write( "Check my calculations, please.\r
\n" ); document.write( "\n" ); document.write( "Dimensions:\r
\n" ); document.write( "\n" ); document.write( "Diameter; 22.5\"\r
\n" ); document.write( "\n" ); document.write( "Height; 33.5\"\r
\n" ); document.write( "\n" ); document.write( "Drum is cylindrical, and standing vertical.\r
\n" ); document.write( "\n" ); document.write( "Volume formula; pi * r^2 * h.\r
\n" ); document.write( "\n" ); document.write( "3.1416 * 16.75 * 16.75 * 2 7/8 (2.875) = 2534.06 cu. in.\r
\n" ); document.write( "\n" ); document.write( "2534.06 / 231 = 10.969 = 11 gal.\r
\n" ); document.write( "\n" ); document.write( "Where am I correct ? Answer given is less. \n" ); document.write( "

Algebra.Com's Answer #853821 by timofer(144) $\"\"$ $\"About$

You can put this solution on YOUR website!
Accepting the inside volume capacity is 55 gallons( the assumption could be wrong), then the amount filled at level of
\n" ); document.write( "2 and 7/8 inches should be $\"%28%282%267%2F8%29%2F%2833%261%2F2%29%2955=highlight%284.7%29\"$ gallons.
\n" ); document.write( "(used online calculator) \n" ); document.write( "

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