document.write( "Question 773494: A piece of work can be done by 5 men in 10 days. After 4 days, 3 men were transferred to another job. how many more days will the remaining men finish the job? \n" ); document.write( "
Algebra.Com's Answer #853779 by MathTherapy(10719)\"\" \"About 
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document.write( "A piece of work can be done by 5 men in 10 days. After 4 days, 3 men were transferred to another job. how many more\r\n" );
document.write( "days will the remaining men finish the job?\r\n" );
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document.write( "What the other person has for an answer makes absolutely NO SENSE. How can it take 2 men, just 6 days to complete a job that\r\n" );
document.write( "a group of 5 men, who normally take 10 days to complete the job, worked for 4 days, and then left the 2 men to complete? \r\n" );
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document.write( "5-MAN rate: \"1%2F10\"\r\n" );
document.write( "1-MAN rate: \"1%2F%285%29%2810%29+=+1%2F50\"\r\n" );
document.write( "2-MAN rate: \"2%281%2F50%29+=+2%2F50+=+1%2F25\"\r\n" );
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document.write( "Formula: (Time 1 * rate 1) + Time 2 * rate 2) = 1 (entire job)\r\n" );
document.write( "                               \"4%281%2F10%29+%2B+T%281%2F25%29+=+1\"\r\n" );
document.write( "                                       \"2%2F5+%2B+T%2F25+=+1\"\r\n" );
document.write( "                                      10 + T = 25 ---- Multiplying by LCD, 25 \r\n" );
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document.write( "Time taken for remaining 2 men to complete job, or T = 25 - 10 = 15 days
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