document.write( "Question 1179660: A motorboat traveling with the current went 42 mi in 3.5 h. Traveling against the current, the boat went 18 mi in 3 h. Find the rate of the boat in calm water and the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #853777 by greenestamps(13296)\"\" \"About 
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\n" ); document.write( "After using the given information to find that the speed with the current is 12 mph and the speed against the current is 6 mph, the other tutors solved the problem with formal algebra by using a pair of equations involving the boat speed and the current speed.

\n" ); document.write( "Of course, a formal algebraic solution is possibly what was required.

\n" ); document.write( "However, this kind of problem is so common that, if formal algebra is not required, it can be solved informally with very little effort using logical reasoning.

\n" ); document.write( "If the current speed added to the boat speed is 12 mph and the current speed subtracted from the boat speed is 6 mph, then logical reasoning says that the boat speed is halfway between 12 mph and 6mph -- i.e., 9 mph -- and the current speed is then the difference between 9 mph and either 6 mph of 12 mph.

\n" ); document.write( "ANSWERS:
\n" ); document.write( "boat speed: 9 mph (halfway between 6 mph and 12 mph)
\n" ); document.write( "current speed: 12-9 = 3 mph; or 9-6 = 3 mph

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