document.write( "Question 166202: a plane which can fly 520mph in still air flies for 3 hours against a wind and for 2 hours with the same wind. The total distance it covers is 2565 miles. find rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #853756 by MathTherapy(10719)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "a plane which can fly 520mph in still air flies for 3 hours against a wind and for 2 hours with the same wind.\r\n" );
document.write( "The total distance it covers is 2565 miles. find rate of the wind.\r\n" );
document.write( "======================================\r\n" );
document.write( "Speed, in still air: 520 mph\r\n" );
document.write( "\r\n" );
document.write( "Let wind-speed be W\r\n" );
document.write( "Average speed, against the wind: 520 - W\r\n" );
document.write( "Average speed, with the wind: 520 + W \r\n" );
document.write( "\r\n" );
document.write( "Distance travelled against the wind, in 3 hours: 3(520 - W) = 1,560 - 3W\r\n" );
document.write( "Distance travelled with the wind, in 2 hours: 2(520 + W) = 1,040 + 2W\r\n" );
document.write( "\r\n" );
document.write( "With the TOTAL DISTANCE travelled being 2,565 miles, we get the following TOTAL DISTANCE equation:\r\n" );
document.write( "1,560 - 3W + 1,040 + 2W = 2,565 \r\n" );
document.write( "      - 3W + 2,600 + 2W = 2,565\r\n" );
document.write( "              - 3W + 2W = 2,565 - 2,600\r\n" );
document.write( "                    - W = - 35\r\n" );
document.write( "   Speed of wind, or
\n" ); document.write( "
\n" );