document.write( "Question 1179662: Divide 75 into two parts so that one part is 2/3 of the other. \n" ); document.write( "
Algebra.Com's Answer #853752 by ikleyn(53727) You can put this solution on YOUR website! . \n" ); document.write( "Divide 75 into two parts so that one part is 2/3 of the other. \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Calculations in the post by @mananth are incorrect.\r \n" ); document.write( "\n" ); document.write( " I came to bring a correct solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If one part is x \n" ); document.write( "the other part will be 2x/3 \n" ); document.write( "x+ 2x/3 =75 \n" ); document.write( "(3x+2x)/3=75 \n" ); document.write( "5x = 225 \n" ); document.write( "x = 45 \n" ); document.write( "You can find the other part \n" ); document.write( "2/3 x = 2/3 * 45 = 30.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ANSWER. The parts are 45 cm and 30 cm.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved correctly.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |