document.write( "Question 99970: Please help. I have one last problem on my test due tonight. I know I am not giving you a lot of time but the person that usually helps me has ended up in the hospital and I am stuck on this last question.\r
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document.write( "Solve sqrt2x-1=sqrt4x-1 with another -1 outside the sqrt part.\r
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document.write( "Thanks if you have the time. \n" );
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Algebra.Com's Answer #853749 by MathTherapy(10704) You can put this solution on YOUR website! \r\n" ); document.write( "Please help. I have one last problem on my test due tonight. I know I am not giving you a lot of time but the person that usually helps me has ended up in the hospital and I am stuck on this last question.\r\n" ); document.write( "\r\n" ); document.write( "Solve sqrt2x-1=sqrt4x-1 with another -1 outside the sqrt part.\r\n" ); document.write( "\r\n" ); document.write( "Thanks if you have the time.\r\n" ); document.write( "****************************\r\n" ); document.write( "This does break down to (2x - 1)(2x - 5)=0, as stated by the other person. However, x=-1/2 and x=2/5 are WRONG. \r\n" ); document.write( "Correct answers:\n" ); document.write( " |