document.write( "Question 1158128: 1.If today is Friday,
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document.write( "a. What day of the week will it be 25 days from now?
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document.write( "b. What day of the week was it 32 days ago?
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document.write( " 2. Valentine's Day (Feb. 14) fell on Tuesday in 2017. On what day of the week will Valentine's Day fall in 2032? \n" );
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Algebra.Com's Answer #853714 by ikleyn(53570) You can put this solution on YOUR website! . \n" ); document.write( "1.If today is Friday, \n" ); document.write( "a. What day of the week will it be 25 days from now? \n" ); document.write( "b. What day of the week was it 32 days ago? \n" ); document.write( "2. Valentine's Day (Feb. 14) fell on Tuesday in 2017. On what day of the week will Valentine's Day fall in 2032? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(1a) What day of the week will it be 25 days from now?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " Then the 7-th day from now is Friday, again;\r\n" ); document.write( "\r\n" ); document.write( " the 14-th day from now is Friday, again;\r\n" ); document.write( "\r\n" ); document.write( " the 21-th day from now is Friday, again;\r\n" ); document.write( "\r\n" ); document.write( " the 22-th day is Saturday; the 23-th day is Sunday; the 24-th day is Monday \r\n" ); document.write( "\r\n" ); document.write( " and the 25-th day is Tuesday. <<<---=== ANSWER\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(1b) What day of the week was it 32 days ago?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " Then the 7-th day ago was Friday, again;\r\n" ); document.write( "\r\n" ); document.write( " the 14-th day ago was Friday, again;\r\n" ); document.write( "\r\n" ); document.write( " the 21-th day ago was Friday, again;\r\n" ); document.write( "\r\n" ); document.write( " the 28-th day ago was Friday, again;\r\n" ); document.write( "\r\n" ); document.write( " the 29-th day ago was Thursday; the 30-th day ago was Wednesday; the 31-th day ago was Tuesday \r\n" ); document.write( "\r\n" ); document.write( " and the 32-th day ago was Monday. <<<---=== ANSWER\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(2) Valentine's Day (Feb. 14) fell on Tuesday in 2017. On what day of the week will Valentine's Day fall in 2032 ?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " Let's forget about leap years - we will count them later.\r\n" ); document.write( " So, let's count 365 days per year.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Notice that a 365-days year is 52 weeks PLUS 1 day.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Counting this way, in 7 years from Feb.14,2017, i.e. Feb.14, 1024, it would be Tuesday, again \r\n" ); document.write( " (seven fractional parts of a seven days week will produce a multiple of '7').\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Continuing counting this way, in 7 years from Feb.14,2024, i.e. Feb.14, 1031, it would be Tuesday, again \r\n" ); document.write( " (seven fractional parts of a seven days week will produce a multiple of '7').\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Counting this way, the day Fab.14,2032 would be Wednesday.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Now we should count leap years 2020, 2024, 2028. They give 3 days to add to Wednesday.\r\n" ); document.write( "\r\n" ); document.write( " By adding these 3 days, we obtain Saturday.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " So, the Valentine's day Feb.14,2032 should be Saturday. <<<---=== ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved. All 3 questions are answered.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |