document.write( "Question 280462: This one looked easy but it's got me confused please help and thank you.
\n" ); document.write( "Use the laws of logarithms to express log base2 6 - log base 2 3 + 2 log base 2 sqrt8 as a single logarithm then evaluate. I got this far log base 2^6 - log base2^3 +2 log base 2 sqrt 8 =log base 2 6/3 sqrt8^2??? help
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Algebra.Com's Answer #853679 by greenestamps(13292)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "You have done the harder part of the problem, using the laws of logarithms to write the given expression as a single logarithm. The rest of the problem is simple arithmetic, plus an application of the definition of logarithms:

\n" ); document.write( "\"6%2F3+=+2\"
\n" ); document.write( "\"%28sqrt%288%29%29%5E2=8\"
\n" ); document.write( "\"2%2A8=16\"

\n" ); document.write( "So you have

\n" ); document.write( "\"log%282%2C16%29\"

\n" ); document.write( "which is 4, because \"2%5E4=16\"

\n" ); document.write( "ANSWER: 4

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