document.write( "Question 706087: (4/3)to the 3rd power divided by 2-2/3\r
\n" ); document.write( "\n" ); document.write( "tried several different ways, I know the answer is 16/9 but don't know how to get it.\r
\n" ); document.write( "\n" ); document.write( "I tried.\r
\n" ); document.write( "\n" ); document.write( "64/27 x -4/3 then I flipped to -3/4\r
\n" ); document.write( "\n" ); document.write( "came up with 61/23\r
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Algebra.Com's Answer #853662 by MathTherapy(10719)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "(4/3)to the 3rd power divided by 2-2/3\r\n" );
document.write( "\r\n" );
document.write( "tried several different ways, I know the answer is 16/9 but don't know how to get it.\r\n" );
document.write( "\r\n" );
document.write( "I tried.\r\n" );
document.write( "\r\n" );
document.write( "64/27 x -4/3 then I flipped to -3/4\r\n" );
document.write( "\r\n" );
document.write( "came up with 61/23\r\n" );
document.write( "==================\r\n" );
document.write( "You're trying to do too much. It's much easier doing it this way!\r\n" );
document.write( "\"%284%2F3%29%5E3%2F%282+-+2%2F3%29\" = \"%284%2F3%29%5E3%2F%281%261%2F3%29\" = \"%284%2F3%29%5E3%2F%284%2F3%29\" = \"%284%2F3%29%5E3%2F%284%2F3%29%5E1\" = \"%284%2F3%29%5E%283+-+1%29+=+%284%2F3%29%5E2+=+4%5E2%2F3%5E2+=+highlight%2816%2F9%29\" 
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