document.write( "Question 80251: log 4x= log 5+log(x+1) \n" ); document.write( "
Algebra.Com's Answer #853652 by MathTherapy(10699)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "log 4x= log 5+log(x+1)\r\n" );
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document.write( "Other person's solution. x = - 5. is EXTRANEOUS, so there are NO SOLUTIONS to this equation!\r\n" );
document.write( "For a VALID solution, x MUST be > 0
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