document.write( "Question 5994: This equation is giving me issues.
\n" ); document.write( "log(base2)(x-6)+log(base2)(x-4)-log(base2)x = 2\r
\n" ); document.write( "\n" ); document.write( "Solve for x. Reject any value of x that produces the logarithm of a negative number or 0.
\n" ); document.write( "What I've done:\r
\n" ); document.write( "\n" ); document.write( "log(base2)(x-6)(x-4)-log(base2)x = 2\r
\n" ); document.write( "\n" ); document.write( "log(base2)(x-6)(x-4)/x = 2\r
\n" ); document.write( "\n" ); document.write( "(x-6)(x-4)/x = 2^2 = 4\r
\n" ); document.write( "\n" ); document.write( "4 = (x-6)(x-4)/x
\n" ); document.write( "There is where I am stuck.
\n" ); document.write( "Some help on this would be great. Thanks.
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Algebra.Com's Answer #853647 by MathTherapy(10699)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "This equation is giving me issues.\r\n" );
document.write( "log(base2)(x-6)+log(base2)(x-4)-log(base2)x = 2\r\n" );
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document.write( "Solve for x. Reject any value of x that produces the logarithm of a negative number or 0.\r\n" );
document.write( "What I've done:\r\n" );
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document.write( "log(base2)(x-6)(x-4)-log(base2)x = 2\r\n" );
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document.write( "log(base2)(x-6)(x-4)/x = 2\r\n" );
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document.write( "(x-6)(x-4)/x = 2^2 = 4\r\n" );
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document.write( "4 = (x-6)(x-4)/x\r\n" );
document.write( "There is where I am stuck.\r\n" );
document.write( "Some help on this would be great. Thanks.\r\n" );
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document.write( "The person who responded is PARTIALLY WRONG!!\r\n" );
document.write( "\"log+%282%2C+%28x+-+6%29%29+%2B+log+%282%2C+%28x+-+4%29%29+-+log+%282%2C+%28x%29%29+=+2\"\r\n" );
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document.write( "The smallest of the 3 logs is x - 6, so x - 6 MUST be > 0, and so, x > 6.\r\n" );
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document.write( "So, we get: \"log+%282%2C+%28x+-+6%29%29+%2B+log+%282%2C+%28x+-+4%29%29+-+log+%282%2C+%28x%29%29+=+2\", with x > 6\r\n" );
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document.write( "The person who responded has solutions, x = 12 and x = 2, but as you can see, the x value, 12 is > 6, but the\r\n" );
document.write( "other value 2, is NOT, thereby making the solution, x = 12, ACCEPTABLE, and x = 2, EXTRANEOUS, and UNACCEPTABLE!\r\n" );
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document.write( "The person must've missed this: Reject any value of x that produces the logarithm of a negative number or 0.
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