document.write( "Question 1210551: In equiangular octagaon EFGHIJKL, we know that EF = GH = IJ = KL = 1 and FG = HI = JK = LE = sqrt(2). Find the area of the octagon. \n" ); document.write( "
Algebra.Com's Answer #853645 by ikleyn(53646)\"\" \"About 
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\n" ); document.write( "In equiangular octagon EFGHIJKL, we know that EF = GH = IJ = KL = 1 and FG = HI = JK = LE = sqrt(2).
\n" ); document.write( "Find the area of the octagon.
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document.write( "Let's write the sequence of side lengths in the row\r\n" );
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document.write( "      EF     FG     GH     HI     IJ    JK     KL    LE\r\n" );
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document.write( "       1   sqrt(2)   1   sqrt(2)   1   sqrt(2)  1   sqrt(2)   <<<---===  (1)\r\n" );
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document.write( "You see the repeating pattern as a cycle.\r\n" );
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document.write( "All interior angles are  \"%28180%2A%28n-2%29%29%2Fn\" = \"%28180%2A%288-2%29%29%2F8\" = \"%28180%2A6%29%2F8\" = \"%28180%2A3%29%2F4\" = 45*3 = 135 degrees.\r\n" );
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document.write( "You can calculate the length of the diagonal EG using the cosine law formula\r\n" );
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document.write( "    \"EG%5E2\" = \"EF%5E2+%2B+FG%5E2+-+2%2AEF%2AFG%2Acos%28135%5Eo%29\" = \"1+%2B+2+-2%2A1%2Asqrt%282%29%2A%28-sqrt%282%29%2F2%29%29\" = \"3+%2B+2\" = 5.\r\n" );
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document.write( "so  EG = \"sqrt%285%29\".\r\n" );
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document.write( "Obviously, all such sides EG, GI, IK and KE have the same length  \"sqrt%285%29\"  due to the same reason (the same logic).\r\n" );
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document.write( "Next, this octagon has a remarkable symmetry: if you rotate it in a way that vertex E goes to vertex G\r\n" );
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document.write( "    E ---> G,\r\n" );
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document.write( "then the new octagon (the image under this rotation) will coincide with the original octagon.\r\n" );
document.write( "(simply because the sequence of side lengths (1) will be the same and all interior angles are congruent).\r\n" );
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document.write( "It means that the quadrilateral FHJK will map into and onto itself.\r\n" );
document.write( "It means that this quadrilateral is a square.\r\n" );
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document.write( "   If such reasoning confuses you, you can  notice that sides FH and HJ of the quadrilateral FHJK are orthogonal\r\n" );
document.write( "   since two times angle 135 degs is 270 degs.  And, similarly, quadrilateral FHJK has all his consecutive sides \r\n" );
document.write( "   orthogonal with equal lengths, so this quadrilateral is a square.\r\n" );
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document.write( "Now, the area of the square FHJK is the square of its side, i.e.  \"%28sqrt%285%29%29%5E2\" = 5.\r\n" );
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document.write( "Now you can calculate the area of triangle EFG\r\n" );
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document.write( "    \"area%5BEFG%5D\" = \"%281%2F2%29%2AEF%2AFG%2Asin%28135%5Eo%29\" = \"%281%2F2%29%2A1%2Asqrt%282%29%2A%28sqrt%282%29%2F2%29\" = \"2%2F4\" = \"1%2F2\".\r\n" );
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document.write( "We have 4 such triangles as EFG, so their total area is  \"4%2A%281%2F2%29\" = 2.\r\n" );
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document.write( "Now the total area of the octagon EFGHIJKL is the sum of the area of square FHGK PLUS four triangles\r\n" );
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document.write( "    5 + 2 = 7.\r\n" );
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document.write( "At this point, the solution is complete.\r\n" );
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document.write( "The area of the octagon EFGHIJKL is 7 square units.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Nice problem.   It is a fun to solve it.\r
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