document.write( "Question 1179758: there were 24 nickles, dimes, and quarters whose total value equaled $4.25. how many coins of each kind were there if the number of nickels equaled the number of dimes? \n" ); document.write( "

Algebra.Com's Answer #853617 by ikleyn(53538) $\"\"$ $\"About$

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\n" ); document.write( "there were 24 nickles, dimes, and quarters whose total value equaled $4.25.
\n" ); document.write( "how many coins of each kind were there if the number of nickels equaled the number of dimes?
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\n" ); document.write( "\n" ); document.write( " Here is very simple way to solve this problem for 3 unknowns using only one equation.\r
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document.write( "Let x be the number of nickels.\r\n" );
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document.write( "Then the number of dimes also is x, according to the problem.\r\n" );
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document.write( "Then the number of quarters is  24-x-x = 24-2x.\r\n" );
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document.write( "Now write the total money equation\r\n" );
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document.write( "    5x + 10x + 25*(24-2x) = 425  cents.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    15x + 600 - 50x = 425\r\n" );
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document.write( "    600 - 425 = 50x - 15x\r\n" );
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document.write( "       175    =    35x\r\n" );
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document.write( "         x    =     175/35 = 5.\r\n" );
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document.write( "ANSWER.  5 nickels, 5 dimes and 24-5-5 = 14 quarters.\r\n" );
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document.write( "CHECK  for the total money  5*5 + 5*10 + 14*25 = 425 cents.   ! correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved completely, using only one equation.\r
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