document.write( "Question 744476: 1. Show that log(base 1/c)x = log(base c)1/x\r
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Algebra.Com's Answer #853613 by MathTherapy(10699)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "1. Show that log(base 1/c)x = log(base c)1/x\r\n" );
document.write( "\r\n" );
document.write( "Can you please help me out? Thanks so much in advance:)\r\n" );
document.write( "Can you please show all the steps it would really help me understand:)\r\n" );
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document.write( "      \"log+%281%2Fc%2C+%28x%29%29+=+log+%28c%2C+%281%2Fx%29%29\"\r\n" );
document.write( "      Focusing on the left side only, we get:\r\n" );
document.write( "      \"log+%28%28x%29%29%2Flog+%28%281%2Fc%29%29+=+log+%28c%2C+%281%2Fx%29%29\"\r\n" );
document.write( "    \"log+%28c%2C+%28x%29%29%2Flog+%28c%2C+%281%2Fc%29%29\" = \"log+%28c%2C+%281%2Fx%29%29\"  ----- Changing to base c on left side\r\n" );
document.write( "     \"log+%28c%2C+%28x%29%29%2F%28-+1%29\" = \"log+%28c%2C+%281%2Fx%29%29\"  ----- Changing \"log+%28c%2C+%281%2Fc%29%29\" to - 1, as \"c%5E%28-+1%29+=+1%2Fc\"\r\n" );
document.write( "   \"-+log+%28c%2C+%28x%29%29\" = \"log+%28c%2C+%281%2Fx%29%29\"\r\n" );
document.write( "\"log+%28c%2C+%28x%5E%28-+1%29%29%29\" = \"log+%28c%2C+%281%2Fx%29%29\"\r\n" );
document.write( "  \"highlight%28highlight%28log+%28c%2C+%281%2Fx%29%29%29%29\" = \"highlight%28highlight%28log+%28c%2C+%281%2Fx%29%29%29%29\" <==== PROVEN
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