document.write( "Question 17662: A car radiator holds 24 L of a 20% antifreeze solution. How much of the 20% solution should be drained and be replaced with pure antifreeze to give a 40% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #8536 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Begin with 24 L of .20 antifreeze \n" ); document.write( "Drain x L of .20 antifreeze \n" ); document.write( "Add x L of 1.00 antifreeze\r \n" ); document.write( "\n" ); document.write( "Equals 24 L. of .40 antifreeze\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation: \n" ); document.write( ".20(24) - .20x + 1.00x = .40(24) \n" ); document.write( "4.80 + .80x = 9.60 \n" ); document.write( "4.80-4.80 +.80x = 9.60 - 4.80 \n" ); document.write( ".80x = 4.80 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |