document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1182591>Question 1182591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 0.5 kg block initially at rest on a frictionless horizontal surface is acted <BR>\n" );
document.write( "upon by a force of 8.0 N for a distance of 4.0 m how much kinetic energy does the block gain </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #853592 by </B><A HREF=/tutors/aboutme.mpl?userid=CPhill><B>CPhill(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CPhill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CPhill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=853592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Change in Kinetic energy = Work done on object<BR>\n" );
document.write( "Work done = F * D<BR>\n" );
document.write( "=8.8N *4m<BR>\n" );
document.write( "= 35.2 J<BR>\n" );
document.write( "Therefore, block gains<BR>\n" );
document.write( "35.2 Joule of Kinetic energy.  </SPAN>\n" );
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