document.write( "Question 1181303: Carlo can type a manuscript for 10 hours. he started working then bobby joined him 2 hours later. they worked together for 4 hrs until carlo decided to stop and then bobby had to finish the manuscript alone. if bobby finished the remaining portion in 6 more hours, how long can he type the whole manuscript working alone? \n" ); document.write( "
Algebra.Com's Answer #853587 by CPhill(2189)\"\" \"About 
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Consider typing a manuscript is 1 job
\n" ); document.write( "Carlo takes 10 hours to do the job alone
\n" ); document.write( "So he does 1/10 of the job in 1 hour
\n" ); document.write( "in the first two hours he does 2/10 of the job ------------A
\n" ); document.write( "let bobby take x hours to do the job alpne
\n" ); document.write( "so he does 1/x of the job in 1 hour
\n" ); document.write( "together they do (1/10 +1/x ) of the job in 1 hour
\n" ); document.write( "they work together for4 hours.
\n" ); document.write( "so they do 4 (1/10 + 1/x ) job = 4(10+x)/10x = 2(10+x)/5x of the job-----B
\n" ); document.write( "Booby works for 6 hours
\n" ); document.write( "so he does 6/x of the job -------------C
\n" ); document.write( "A+B+c = 1 job
\n" ); document.write( "2/10 + 2(10+x)/5x + 6/x =1
\n" ); document.write( "Solve for x
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