document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96205>Question 96205</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534954146/algebrahomeworkh>Fundamentals of Alg and Trig</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem:\r<BR>\n" );
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document.write( "y^4/3 = -3y\r<BR>\n" );
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document.write( "This is what I have done:<BR>\n" );
document.write( "y^4/3 + 3y =0\r<BR>\n" );
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document.write( "1. The exp of y is understood to be 1...so does this mean that I need to find the commoon denominator of the exp so that I could add?  Should the exp of 3y then be 1/3?<BR>\n" );
document.write( "y^4/3 + 3y^1/3= 0\r<BR>\n" );
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document.write( "2. Then in the book it says to factor out maybe 1/3?\r<BR>\n" );
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document.write( "This is where I get confused, because the problem in the book that is simmilar looks like this:<BR>\n" );
document.write( "x^3/2= x^1/2<BR>\n" );
document.write( "x^3/2- x^1/2= 0<BR>\n" );
document.write( "x^1/2(x-1)) =0   How are they factoring out x^1/2?  Is x^1/2(x-1) = x^3/2 -x^1/2\r<BR>\n" );
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document.write( "3. So once they get x^1/2= 0   and x-1=0\r<BR>\n" );
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document.write( "so the answer is x=0 and x=1  </SPAN>\n" );
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document.write( "...<br><BR>\n" );
document.write( "This is what I have done:<BR>\n" );
document.write( "y^4/3 + 3y =0<BR>\n" );
document.write( "1. The exp of y is understood to be 1...so does this mean that I need to find the commoon denominator of the exp so that I could add? Should the exp of 3y then be 1/3?<BR>\n" );
document.write( "y^4/3 + 3y^1/3= 0<br><br><BR>\n" );
document.write( "No.<br><BR>\n" );
document.write( "As the other tutor says, you seem to be trying to make this problem look like the example in your book, but it is very different.<br><BR>\n" );
document.write( "In the expression \"3y\" in this problem, the understood exponent \"1\" is only the exponent of \"y\" -- it is not the exponent of \"3y\".<br><BR>\n" );
document.write( "Leave the equation as<br><BR>\n" );
document.write( "y^4/3 + 3y =0<br><BR>\n" );
document.write( "Then, as the other tutor shows, factor out the common factor \"y\" on the left and solve the problem from there.<br>\r<BR>\n" );
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document.write( " </SPAN>\n" );
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