document.write( "Question 1201447: The denominator of a fraction is 8 more than the numerator. If both the numerator and denominator are decreased by 5, then the resulting fraction becomes 2/3. Find the original fraction \n" ); document.write( "

Algebra.Com's Answer #853540 by ikleyn(53646) $\"\"$ $\"About$

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\n" ); document.write( "The denominator of a fraction is 8 more than the numerator. If both the numerator and denominator
\n" ); document.write( "are decreased by 5, then the resulting fraction becomes 2/3. Find the original fraction
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\n" ); document.write( "\n" ); document.write( "It can be easily solved using one unknown and one equation.\r
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document.write( "Let x be the numerator of the fraction.\r\n" );
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document.write( "Then the denominator is (x+8).\r\n" );
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document.write( "Decreased values are (x-5) for the numerator and ((x+8)-5) = (x+3) for the denominator.\r\n" );
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document.write( "Write equation for modified fraction\r\n" );
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document.write( "     = .\r\n" );
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document.write( "Cross-multiply and find x\r\n" );
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document.write( "    3(x-5) = 2(x+3),\r\n" );
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document.write( "    3x - 15 = 2x + 6,\r\n" );
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document.write( "    3x - 2x = 6 + 15.\r\n" );
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document.write( "       x    =   21.\r\n" );
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document.write( "The original fraction is   = .    <<<---===  ANSWER\r\n" );
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