document.write( "Question 871834: Hi and thanks for the help! I was wondering how to solve log base square root 3 to the 1/9=x. also one other question is to change the exponential equation to a log... x^3=729 \n" ); document.write( "
Algebra.Com's Answer #853529 by MathTherapy(10699)\"\" \"About 
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document.write( "Hi and thanks for the help! I was wondering how to solve log base square root 3 to the 1/9=x. also one other question is\r\n" );
document.write( "to change the exponential equation to a log... x^3=729 \r\n" );
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document.write( "If \"log+%28sqrt%283%29%2C+%281%2F9%29%29+=+x\", then:\r\n" );
document.write( "       \"%28sqrt%283%29%29%5Ex+=+1%2F9+\" ---- Converting to EXPONENTIAL form\r\n" );
document.write( "   \"matrix%282%2C1%2C+%22+%22%2C+%283%5E%281%2F2%29%29%5Ex%29+=+1%2F9\" ---- Converting \"sqrt%283%29\" to \"matrix%282%2C1%2C+%22+%22%2C+3%5E%281%2F2%29%29\"\r\n" );
document.write( "       \"matrix%282%2C1%2C+%22%22%2C+3%5E%28x%2F2%29%29+=+1%2F9\"\r\n" );
document.write( "      \"matrix%281%2C2%2C+matrix%282%2C1%2C+%22+%22%2C+3%5E%28x%2F2%29%29%2C+%22=%22%29%29\"\"matrix%282%2C1%2C+%22+%22%2C+3%5E%28++-++2%29%29\"\r\n" );
document.write( "          \"x%2F2+=++-++2\" ----- Bases are equal, and so are the exponents\r\n" );
document.write( "          x = 2(- 2) = - 4
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