document.write( "Question 1164833: Given the following logical expression, place the operations in the order in which you would apply, from first operation to last.\r
\n" ); document.write( "\n" ); document.write( "p → q ∨ ~r
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Algebra.Com's Answer #853510 by CPhill(2189)\"\" \"About 
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To determine the correct order of operations for the logical expression , we follow the standard rules of **operator precedence** in propositional logic.\r
\n" ); document.write( "\n" ); document.write( "The general hierarchy of operations is:\r
\n" ); document.write( "\n" ); document.write( "1. **Parentheses** (None in this expression)
\n" ); document.write( "2. **Negation** ( or )
\n" ); document.write( "3. **Conjunction** () and **Disjunction** ()
\n" ); document.write( "4. **Conditional** ()
\n" ); document.write( "5. **Biconditional** ()\r
\n" ); document.write( "\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "### Order of Application\r
\n" ); document.write( "\n" ); document.write( "Based on these rules, here is the order in which you would apply the operations for this expression:\r
\n" ); document.write( "\n" ); document.write( "1. **First Operation: Negation ()**
\n" ); document.write( "You must first find the truth value of \"not \" before it can be used in any other operation.
\n" ); document.write( "2. **Second Operation: Disjunction ()**
\n" ); document.write( "Following the hierarchy, the \"OR\" () operator is applied next. You take the result of and combine it with .
\n" ); document.write( "3. **Last Operation: Conditional ()**
\n" ); document.write( "The arrow (if-then) is the \"main operator\" here. It is applied last, using as the antecedent and the entire result of the previous step as the consequent.\r
\n" ); document.write( "\n" ); document.write( "### Summary Table\r
\n" ); document.write( "\n" ); document.write( "| Step | Operation | Name | Resulting Sub-expression |
\n" ); document.write( "| --- | --- | --- | --- |
\n" ); document.write( "| 1 | | Negation | |
\n" ); document.write( "| 2 | | Disjunction | |
\n" ); document.write( "| 3 | | Conditional | |\r
\n" ); document.write( "\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "Would you like me to construct a **truth table** for this expression to see how these operations interact?
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