document.write( "Question 1164833: Given the following logical expression, place the operations in the order in which you would apply, from first operation to last.\r
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document.write( "p → q ∨ ~r \n" );
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Algebra.Com's Answer #853510 by CPhill(2189) You can put this solution on YOUR website! To determine the correct order of operations for the logical expression , we follow the standard rules of **operator precedence** in propositional logic.\r \n" ); document.write( "\n" ); document.write( "The general hierarchy of operations is:\r \n" ); document.write( "\n" ); document.write( "1. **Parentheses** (None in this expression) \n" ); document.write( "2. **Negation** ( or ) \n" ); document.write( "3. **Conjunction** () and **Disjunction** () \n" ); document.write( "4. **Conditional** () \n" ); document.write( "5. **Biconditional** ()\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### Order of Application\r \n" ); document.write( "\n" ); document.write( "Based on these rules, here is the order in which you would apply the operations for this expression:\r \n" ); document.write( "\n" ); document.write( "1. **First Operation: Negation ()** \n" ); document.write( "You must first find the truth value of \"not \" before it can be used in any other operation. \n" ); document.write( "2. **Second Operation: Disjunction ()** \n" ); document.write( "Following the hierarchy, the \"OR\" () operator is applied next. You take the result of and combine it with . \n" ); document.write( "3. **Last Operation: Conditional ()** \n" ); document.write( "The arrow (if-then) is the \"main operator\" here. It is applied last, using as the antecedent and the entire result of the previous step as the consequent.\r \n" ); document.write( "\n" ); document.write( "### Summary Table\r \n" ); document.write( "\n" ); document.write( "| Step | Operation | Name | Resulting Sub-expression | \n" ); document.write( "| --- | --- | --- | --- | \n" ); document.write( "| 1 | | Negation | | \n" ); document.write( "| 2 | | Disjunction | | \n" ); document.write( "| 3 | | Conditional | |\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "Would you like me to construct a **truth table** for this expression to see how these operations interact? \n" ); document.write( " |