document.write( "Question 1164883: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is $176,000. Assume the standard deviation is $32,000. Suppose you take a simple random sample of 48 graduates. Round all answers to four decimal places if necessary.\r
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document.write( "What is the distribution of
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document.write( "What is the distribution of
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document.write( "For a single randomly selected graduate, find the probability that her salary is between $178,172 and $184,181. \r
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document.write( "For a simple random sample of 48 graduates, find the probability that the average salary is between $178,172 and $184,181. \r
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document.write( "For part d), is the assumption of normal necessary? No or Yes \n" );
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Algebra.Com's Answer #853507 by CPhill(2189) You can put this solution on YOUR website! To solve this, we use the principles of the Normal Distribution and the **Central Limit Theorem**.\r \n" ); document.write( "\n" ); document.write( "### a) What is the distribution of ?\r \n" ); document.write( "\n" ); document.write( "The distribution of the individual annual salaries () follows the population mean and standard deviation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "### b) What is the distribution of ?\r \n" ); document.write( "\n" ); document.write( "For a sample of size , the sampling distribution of the mean () is also normal, but with a smaller standard deviation (Standard Error).\r \n" ); document.write( "\n" ); document.write( "* **Mean ():** \n" ); document.write( "* **Standard Error ():** \r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### c) For a single randomly selected graduate, find the probability that her salary is between $178,172 and $184,181.\r \n" ); document.write( "\n" ); document.write( "We need to find . We calculate the -scores for both values:\r \n" ); document.write( "\n" ); document.write( "* \n" ); document.write( "* \r \n" ); document.write( "\n" ); document.write( "Using a standard normal distribution table or calculator:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "**Probability = 0.0738**\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### d) For a simple random sample of 48 graduates, find the probability that the average salary is between $178,172 and $184,181.\r \n" ); document.write( "\n" ); document.write( "We use the Standard Error () to find the -scores for the sample mean:\r \n" ); document.write( "\n" ); document.write( "* \n" ); document.write( "* \r \n" ); document.write( "\n" ); document.write( "Using a standard normal distribution table or calculator:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "**Probability = 0.2808**\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### e) For part d), is the assumption of normal necessary?\r \n" ); document.write( "\n" ); document.write( "**No**. \n" ); document.write( "Because the sample size () is greater than 30, the **Central Limit Theorem** ensures that the sampling distribution of the mean will be approximately normal even if the underlying population distribution is not.\r \n" ); document.write( "\n" ); document.write( "Would you like me to explain how the probability would change if the sample size was smaller, say ? \n" ); document.write( " |