document.write( "Question 1164884: CNNBC recently reported that the mean annual cost of auto insurance is 1036 dollars. Assume the standard deviation is 268 dollars, and the cost is normally distributed. You take a simple random sample of 35 auto insurance policies. Round your answers to 4 decimal places.\r
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document.write( "What is the distribution of X?X~ N(________,_______)\r
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document.write( "What is the distribution of ¯x?¯x~ N(________,__________)\r
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document.write( "What is the probability that one randomly selected auto insurance is less than $996? \r
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document.write( "a simple random sample of 35 auto insurance policies, find the probability that the average cost is less than $996. \r
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document.write( "For part d), is the assumption of normal necessary? Yes or No \n" );
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Algebra.Com's Answer #853506 by CPhill(2189) You can put this solution on YOUR website! To solve this, we will use the parameters of the population and the **Central Limit Theorem** to find the probabilities for both an individual policy and a sample mean.\r \n" ); document.write( "\n" ); document.write( "### a) What is the distribution of ?\r \n" ); document.write( "\n" ); document.write( "The distribution of individual auto insurance costs () is given as normally distributed with the population mean and standard deviation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "### b) What is the distribution of ?\r \n" ); document.write( "\n" ); document.write( "For a sample of size , the sampling distribution of the mean () is also normal.\r \n" ); document.write( "\n" ); document.write( "* **Mean ():** Equal to the population mean, **1036**. \n" ); document.write( "* **Standard Error ():** Calculated as .\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### c) What is the probability that one randomly selected auto insurance is less than $996?\r \n" ); document.write( "\n" ); document.write( "We need to find . First, we calculate the -score:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using a standard normal distribution table or calculator for : \n" ); document.write( "**Probability = 0.4407**\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### d) For a simple random sample of 35 auto insurance policies, find the probability that the average cost is less than $996.\r \n" ); document.write( "\n" ); document.write( "We need to find . We use the standard error () to find the new -score:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using a standard normal distribution table or calculator for : \n" ); document.write( "**Probability = 0.1886**\r \n" ); document.write( "\n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "### e) For part d), is the assumption of normal necessary?\r \n" ); document.write( "\n" ); document.write( "**No**. \n" ); document.write( "Even if the original population were not normally distributed, the **Central Limit Theorem** states that the sampling distribution of the mean will be approximately normal because the sample size () is greater than 30.\r \n" ); document.write( "\n" ); document.write( "Would you like me to show you how the probability changes if we increase the sample size to 100? \n" ); document.write( " |