document.write( "Question 933453: Log(base 2) (x+14)+log(base 2)x=5 \n" ); document.write( "

Algebra.Com's Answer #853493 by MathTherapy(10699) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "Log(base 2) (x+14)+log(base 2)x=5\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Smaller variable-expression, x, MUST be > 0. We then get: x MUST be > 0. The problem then becomes:\r\n" );
document.write( ", with x > 0.\r\n" );
document.write( "        ---- Applying  = \r\n" );
document.write( "              --- Converting to EXPONENTIAL form\r\n" );
document.write( "             \r\n" );
document.write( "         \r\n" );
document.write( "     (x - 2)(x + 16) = 0 ----- Factoring TRINOMIAL\r\n" );
document.write( "      x - 2 = 0      OR      x + 16 = 0 --- Setting each factor = to 0\r\n" );
document.write( "         x = 2      OR           x = - 16 (IGNORE).\r\n" );
document.write( "\r\n" );
document.write( "x = 2 is the ONLY solution, since the other value, - 16, is NOT > 0.

\n" ); document.write( "

\n" );