document.write( "Question 975452: 0= log base 5 (x-2) - log base 5 (2x) \n" ); document.write( "
Algebra.Com's Answer #853490 by MathTherapy(10699)\"\" \"About 
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document.write( "0= log base 5 (x-2) - log base 5 (2x)\r\n" );
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document.write( "\"0+=+log+%285%2C+%28x+-+2%29%29+-+log+%285%2C+%282x%29%29\"\r\n" );
document.write( "Smaller variable-expression, x - 2 MUST be > 0. We then get: x - 2 > 0___x MUST be > 2. The problem then becomes:\r\n" );
document.write( "\"0+=+log+%285%2C+%28x+-+2%29%29+-+log+%285%2C+%282x%29%29\", with x > 2.\r\n" );
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document.write( "When solved, we get x = - 2. However, because this x-value is NOT > 2, there are NO SOLUTIONS to this LOGARITHMIC equation.\r\n" );
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document.write( "So, IGNORE the other person's answer that x = - 2.
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