document.write( "Question 315119: if log(base3)x=7, evaluate the following. log(base3)9x
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Algebra.Com's Answer #853483 by MathTherapy(10699)\"\" \"About 
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document.write( " if log(base3)x=7, evaluate the following. log(base3)9x\r\n" );
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document.write( "   \"log+%283%2C+%28x%29%29+=+7\"\r\n" );
document.write( "  \"log%283%2C+%289x%29%29+=+log+%283%2C+%289%29%29+%2B+log+%283%2C+%28x%29%29\" ---- Applying \"log+%28a%2C+%28bc%29%29+=+log+%28a%2C+%28b%29%29+%2B+log+%28a%2C+%28c%29%29\"\r\n" );
document.write( "\"highlight%28log%283%2C+%289x%29%29%29\" = 2 + 7 = 9 ---- Substituting 2 for \"log+%283%2C+%289%29%29\" and 7 (GIVEN) for \"log+%283%2C+%28x%29%29\"
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