document.write( "Question 1204081: the combined age of 2 brothers is 35 years old.7 years ago one brother was twice the age of the other. how many years apart were they born
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Algebra.Com's Answer #853481 by ikleyn(53618) $\"\"$ $\"About$

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\n" ); document.write( "the combined age of 2 brothers is 35 years old. 7 years ago one brother was twice the age of the other.
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\n" ); document.write( "\n" ); document.write( " Nice/ideal problem to solve it MENTALLY, without using equations.\r
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document.write( "Seven years ago the combined age of the two brothers was 35 - 7 - 7 = 21 years.\r\n" );
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document.write( "In addition, we are given that 7 years ago (i.e., at that time), one brother was twice the age of the other.\r\n" );
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document.write( "It means (as anyone can get immediately), that 7 years ago the older brother was 14 years old,\r\n" );
document.write( "while the younger brother was 7 years old at that time.\r\n" );
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document.write( "Hence, the brothers were born 14-7 = 7 years apart.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "As clear as 2 - 1 = 1.\r
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\n" ); document.write( "\n" ); document.write( "Compare with the solution by @mananth.\r
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