document.write( "Question 921936: log (base 7) 2 + log (base 49) x = log (base 1/7) sqrt 3 \n" ); document.write( "
Algebra.Com's Answer #853469 by MathTherapy(10699)\"\" \"About 
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document.write( "log (base 7) 2 + log (base 49) x = log (base 1/7) sqrt 3\r\n" );
document.write( " \"log+%287%2C+%282%29%29+%2B+log+%2849%2C+%28x%29%29+=+log+%281%2F7%2C+%28sqrt%283%29%29%29\"\r\n" );
document.write( "   \r\n" );
document.write( "  ---- Converting from base 10 to base 7\r\n" );
document.write( "  \r\n" );
document.write( "  \r\n" );
document.write( " ---- Multiplying by LCD, 2\r\n" );
document.write( "  --- Applying \"a%2Alog+%28b%2C+c%29\" = \"log+%28b%2C+%28c%29%5Ea%29\"\r\n" );
document.write( "  \"log+%287%2C+%284%29%29+%2B+log+%287%2C+%28x%29%29+=+log+%287%2C+%281%2Fsqrt%283%29%29%5E2%29\"\r\n" );
document.write( "  \"log+%287%2C+%284%29%29+%2B+log+%287%2C+%28x%29%29+=+log+%287%2C+%281%2F3%29%29\"\r\n" );
document.write( "\r\n" );
document.write( "         \"log+%287%2C+%284x%29%29+=+log+%287%2C+%281%2F3%29%29\" ---- Applying \"log+%28a%2C+%28b%29%29+%2B+log+%28a%2C+%28c%29%29+=+log+%28a%2C+%28b%2Ac%29%29\"\r\n" );
document.write( "               \"4x+=+1%2F3\" ---- Applying b = c, WHEN \"log+%28a%2C+%28b%29%29+=+log+%28a%2C+%28c%29%29\" \r\n" );
document.write( "              12x = 1 ------ Cross-multiplying\r\n" );
document.write( "               \"highlight%28x+=+1%2F12%29\"
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