document.write( "Question 58555: 5) Logarithms:
\n" ); document.write( "a) Using a calculator, find log 1000 where log means log to the base of 10.
\n" ); document.write( "Answer: \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "b) Most calculators have 2 different logs on them: log, which is base 10, and ln, which is base e. In computer science, digital computers are based on the binary numbering system which means that there are only 2 numbers available to the computer, 0 and 1. When a computer scientist needs a logarithm, he needs a log to base 2 which is not on any calculator. To find the log of a number to any base, we can use a conversion formula as shown here:
\n" ); document.write( "log b a=log-a/log-b
\n" ); document.write( "
\n" ); document.write( "Using this formula, find log sqr 1000 . Round your answer to the hundredth's place.
\n" ); document.write( "Answer:
\n" ); document.write( "Show work in this space. \r
\n" ); document.write( "\n" ); document.write( "thanks Tine I am having the hardwst time with these could you give me some dirrection thanks?
\n" ); document.write( "

Algebra.Com's Answer #853418 by MathTherapy(10806)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "5) 	Logarithms:\r\n" );
document.write( "a) 	Using a calculator, find log 1000 where log means log to the base of 10. \r\n" );
document.write( "Answer: \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "b) 	Most calculators have 2 different logs on them: log, which is base 10, and ln, which is base e. In computer\r\n" );
document.write( "science, digital computers are based on the binary numbering system which means that there are only 2 numbers\r\n" );
document.write( "available to the computer, 0 and 1. When a computer scientist needs a logarithm, he needs a log to base 2 which\r\n" );
document.write( "is not on any calculator. To find the log of a number to any base, we can use a conversion formula as shown here:\r\n" );
document.write( "log b  a=log-a/log-b\r\n" );
document.write( " \r\n" );
document.write( "Using this formula, find log sqr 1000 . Round your answer to the hundredth's place.\r\n" );
document.write( "Answer:  \r\n" );
document.write( "Show work in this space.   \r\n" );
document.write( "\r\n" );
document.write( "thanks Tine I am having the hardwst time with these could you give me some dirrection thanks?\r\n" );
document.write( "\r\n" );
document.write( "log b  a=log-a/log-b is \"saying\" that: \"log+%28b%2C+%28a%29%29+=+%28log+%28%28a%29%29%29%2F%28log+%28%28b%29%29%29\"\r\n" );
document.write( "\"log+%28%28sqrt%28%221%2C000%22%29%29%29\", without a base, denotes base 10. So, we get:\r\n" );
document.write( "\"highlight%28log+%28%28sqrt%28%221%2C000%22%29%29%29%29\" = \"log+%2810%2C+%28sqrt%28%221%2C000%22%29%29%29\" = \"log+%2810%2C+matrix%282%2C1%2C+%22+%22%2C+%28%221%2C000%22%5E%281%2F2%29%29%29%29\" = \"%281%2F2%29log+%2810%2C+%28%221%2C000%22%29%29\" = \"%281%2F2%29%28log+%28%28%221%2C000%22%29%29%2Flog+%28%2810%29%29%29\" = \"%281%2F2%29%283%2F1%29\" = \"3%2F2\" = 1.50
\n" ); document.write( "
\n" );