document.write( "Question 454327: Solve the linear system by using substitution. 3x+2y=5, 5x-9y=-4 \n" ); document.write( "
Algebra.Com's Answer #853397 by ikleyn(53570)\"\" \"About 
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\n" ); document.write( "Solve the linear system by using substitution. 3x+2y=5, 5x-9y=-4
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\n" ); document.write( "\n" ); document.write( "        In his post, @mananth makes 16 tons incorrect calculations.\r
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document.write( "Your starting equations are \r\n" );
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document.write( "    3x + 2y = 5,     (1)\r\n" );
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document.write( "    5x - 9y = -4.    (2)\r\n" );
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document.write( "From equation (1), express  y = \"%28%28-3x%29%2B5%29%2F2\"  and substitute it into equation (2), replacing 'y' there\r\n" );
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document.write( "    5x - \"9%2A%28%28-3x%29%2B5%29%2F2\" = -4.\r\n" );
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document.write( "Multiply both sides by 2 to rid of the numerator\r\n" );
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document.write( "    10x - 9*((-3x)+5) = -8.\r\n" );
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document.write( "Simplify and find 'x' from this equation\r\n" );
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document.write( "    10x + 27x - 45 = -8\r\n" );
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document.write( "    37x = -8 + 45\r\n" );
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document.write( "    37x = 37\r\n" );
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document.write( "      x = 37/37 = 1.\r\n" );
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document.write( "Now substitute x = 1 into equation (1) and find 'y'\r\n" );
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document.write( "    3*1 + 2y = 5  --->  2y = 5 - 3 = 2  --->  y = 2/2 = 1.\r\n" );
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document.write( "ANSWER.  x = 1,  y = 1.\r\n" );
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