document.write( "Question 449831: a circle has a diameter with endpoints (5, -2) and (-13 -6) what are the coordinates of the center of the circle \n" ); document.write( "

Algebra.Com's Answer #853370 by mccravyedwin(420) $\"\"$ $\"About$

You can put this solution on YOUR website!
If the coordinates of A and B are ( x1, y1) and ( x2, y2) respectively, then the midpoint, M, of AB is given by the following formula M = $\"%28x1%2Bx2%29%2F2\"$ $\"%28y1%2By2%29%2F2\"$
\n" ); document.write( "(5,-2)(-13,-6)
\n" ); document.write( "x=(5-13 )/2,y=(-2~~-13~~)/2
\n" ); document.write( "x= -4,y= ~~-7.5~~
\n" ); document.write( "

\r\n" );
document.write( "Correction to mananth(16949)'s solution. She used -13, which was x2 \r\n" );
document.write( "where she should have used -6, which was y2.  So her corrected solution is

\n" ); document.write( " If the coordinates of A and B are ( x1, y1) and ( x2, y2) respectively, then the midpoint, M, of AB is given by the following formula M = $\"%28x1%2Bx2%29%2F2\"$ $\"%28y1%2By2%29%2F2\"$
\n" ); document.write( "(5,-2)(-13,-6)
\n" ); document.write( "x=(5-13 )/2,y=(-2-6)/2
\n" ); document.write( "x= -4,y= -4
\n" ); document.write( "

\r\n" );
document.write( "Edwin

\n" ); document.write( "

\n" );