document.write( "Question 448800: A bicycler traveling 12 mph passes a runner traveling 9 mph. If the runner started at noon, and the bicycler at 12:30, how far from the start point did they meet?
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Algebra.Com's Answer #853358 by ikleyn(53427) $\"\"$ $\"About$

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document.write( "When the bicycler started at 12:30, the runner was 9*0.5 = 4.5 miles ahead.\r\n" );
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document.write( "The approaching speed was  12-9 = 3 mph,  so the bicycler catch up the runner in  4.5/3 = 1.5 hours.\r\n" );
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document.write( "During this time, the bicyclist covered 1.5*12 = 18 miles from the start.\r\n" );
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document.write( "So, the distance from the start to the meeting point was 18 km.    ANSWER\r\n" );
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