document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=446383>Question 446383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Jill fills a pool with water in 30 min, jack fills a pool with water in 45 min and John fills a pool with water in 1 hour and 30 min. How long will it take if they work together.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #853332 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13258)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=853332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative to the standard algebraic method shown by the other tutor.  This method works especially well in this particular problem because the numbers are \"nice\".<br><BR>\n" );
document.write( "The three times for the three people to fill the pool, in minutes, are 30, 45, and 90.<br><BR>\n" );
document.write( "Consider the least common multiple of those times, which is 90 minutes.  In 90 minutes, ...<BR>\n" );
document.write( "Jill could fill the pool 90/30 = 3 times;<BR>\n" );
document.write( "Jack could fill the pool 90/45 = 2 times; and<BR>\n" );
document.write( "John could fill the pools 90/90 = 1 time<br><BR>\n" );
document.write( "Therefore, in 90 minutes, the three of them could fill the pool 3+2+1 = 6 times.<br><BR>\n" );
document.write( "And if they can fill the pool 6 times in 90 minutes, the time it takes them to fill the pool once is 90/6 = 15 minutes.<br><BR>\n" );
document.write( "ANSWER: 15 minutes<br><BR>\n" );
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