document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=117305>Question 117305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The following equation can be used to find the area of a trapezoid.  Solve for the variable b:\r<BR>\n" );
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document.write( "A=1/2h(B+b)\r<BR>\n" );
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document.write( "I can't seem to figure this one out. I know that B + b represent the lenght of the trapezoid and there are four possible solutions we were given: <BR>\n" );
document.write( "B=2A/h<BR>\n" );
document.write( "b=B(A-1/2h)<BR>\n" );
document.write( "b=A-Bh<BR>\n" );
document.write( "b=(2A/h)-B\r<BR>\n" );
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document.write( "It can't be the first one, because I am not looking for B, but for b. <BR>\n" );
document.write( "Any help would be greatly appreciated. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #85330 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=85330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for the variable b: <BR>\n" );
document.write( "A=(1/2)h(B+b)<BR>\n" );
document.write( "2A = h(B+b)<BR>\n" );
document.write( "B+b = (2A)/h<BR>\n" );
document.write( "b = (2a/h) - B<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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