document.write( "Question 442367: 20000$ is split into two investments one paying 5% and the other paying 6.5% to the nearest cent how much should be invested in each so the yearly intrest from the 5% investment is double the intrest from 6.5% investment
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Algebra.Com's Answer #853299 by ikleyn(53427) $\"\"$ $\"About$

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\n" ); document.write( "20000$ is split into two investments one paying 5% and the other paying 6.5%. To the nearest cent how much should be
\n" ); document.write( "invested in each so the yearly interest from the 5% investment is double the interest from 6.5% investment
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\n" ); document.write( "\n" ); document.write( " The solution in the post by @mananth is incorrect due to arithmetic error.\r
\n" ); document.write( "\n" ); document.write( " Below is my correct solution.\r
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document.write( "let investment at  6.5%  be  x.\r\n" );
document.write( "Investment at  5%  is  (20000-x).\r\n" );
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document.write( "0.05*x = 2*0.065*(20000-x)\r\n" );
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document.write( "Multiply by 100 both sides of the equation\r\n" );
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document.write( "    5x = 2*6.5(20000-x)\r\n" );
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document.write( "    5x = 260000 - 13x\r\n" );
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document.write( "    18x = 260000\r\n" );
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document.write( "    x = 260000/18 = 14,444.44 dollars invested at 6.5%.\r\n" );
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document.write( "    The rest, or 20,000 - 14,444.44 = 5,555.56 dollars invested at 5%.\r\n" );
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document.write( "CHECK.  The interest of the 5% investment is  14444.44*0.05 = 722.22.\r\n" );
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document.write( "        The interest of the 6.5% investment is  0.065*5555.56 = 361.11.\r\n" );
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document.write( "        The interest of the 5% investment is the doubled interest of the 6.5% investment.  ! correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved correctly.\r
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